National League for Nursing (NLN PAX) Practice Exam

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If a light bulb has a resistance of 100 ohms and is connected to a voltage of 110 volts, what is the current drawn?

0.1 amperes

1.1 amperes

To determine the current drawn by the light bulb, you can use Ohm's law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R). This can be expressed with the formula:

\[ I = \frac{V}{R} \]

In this scenario, the light bulb has a resistance of 100 ohms and is connected to a voltage of 110 volts. Plugging these values into the formula gives:

\[ I = \frac{110 \, \text{volts}}{100 \, \text{ohms}} = 1.1 \, \text{amperes} \]

This calculation leads to the conclusion that the current drawn by the light bulb is 1.1 amperes, making it the correct answer. This approach to using Ohm’s law is foundational in understanding electrical circuits, as it relates the three fundamental properties of voltage, current, and resistance in a straightforward manner.

10 amperes

11 amperes